expand (2x -1/x)² as a sum of power of x
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Answered by
26
Hi Friend !!!
Here is ur answer,,,
(2x-1/x)² = (2x)² - 2(2x)(1/x) + (1/x)²
= 4x² - 4 + 1/x²
= 4x² - 4 + x^-2
Sum of powers = 2+0-2
= 0
Hope it helps u : )
Here is ur answer,,,
(2x-1/x)² = (2x)² - 2(2x)(1/x) + (1/x)²
= 4x² - 4 + 1/x²
= 4x² - 4 + x^-2
Sum of powers = 2+0-2
= 0
Hope it helps u : )
Answered by
6
Answer:(2x-1/x)² = (2x)² - 2(2x)(1/x) + (1/x)²
= 4x² - 4 + 1/x²
= 4x² - 4 + x^-2
Sum of powers = 2+0-2
= 0
Step-by-step explanation:
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