Question

expand:-(2x+3/X)^3 plz I want this answer​

Answer 1

Step-by-step explanation:

please mark me as brainliest

Answer 2

Answer:

(2x+3)³

=8x³+36x²+54x+27

+54x+27

+54x+27 Explanation:

+54x+27 Explanation:The binomial formula that you need here is

+54x+27 Explanation:The binomial formula that you need here is(a+b)³=a³+3a²b+3ab²+b³

Let me colour the same formula to add clarity:

(a+b)³=a³+3a²b+3ab²+b³

In your case, you would like to expand

In your case, you would like to expand (2x+3)³,

so your

so youra=2x and b=3

so youra=2x and b=3

so youra=2x and b=3 Now, you need to plug 2x for every occurence of a in the formula and plug 3 for everyoccurence of b

for everyoccurence of b in the formula:

for everyoccurence of b in the formula:(2x+3)³=(2x)³+ 3(2x) 2⋅3+32x⋅32+33

=(2x)³+3⋅ (2x)2⋅3+3⋅(2x) ⋅32+33

=23x³+9⋅22x²+3⋅2x⋅9+27

=8x³+36x²+54x+27

Okay!!!!!!