Question

expand (-2x + 3y + 2c)^2 using suitable identities ​

Answer 1

$\huge\bold{\gray{\sf{Answer:}}}$

Explanation:-

Here ,this identity is used:-

${(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + 2zx$

Solving questions according to this identity:-

${( - 2x + 3y + 2c)}^{2} = {( - 2x)}^{2} + {(3y)}^{2} + {(2c)}^{2} + 2( - 2x)(3y) + 2(3y)(2c) + 2(2c)( - 2x)$

$= 4 {x}^{2} + 9 {y}^{2} + 4 {c}^{2} - 12xy + 12cy - 8cx$

Other related identity:-

$\bold{\boxed{ {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy}}$

$\bold{\boxed{{(x + y)}^{3} = {x}^{3} + {y}^{3} + 3xy(x + y)}}$

$\bold{\boxed{ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )}}$

Answer 2

Answer:

Step-by-step explanation:

$x^{3} +y^{3} = (x+y) (x^2-xy+x^2)$   is the answer