Question

Expand( 2x+3y+2z)^2
Using suitable identity

Answer 1

$\bf \large \it \: Hey \: User!!!$

given :- ( 2x + 3y + 2z )²

by using identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac

here a = 2x, b = 3y and c = 2z

( 2x + 3y + 2z )² = (2x)² + (3y)² + (2z)² + 2(2x)(3y) + 2(3y)(2z) + 2(2x)(2z)
= 4x² + 9y² + 4z² + 12xy + 12yz + 12xz

$\bf \large \it \: Cheers!!! \:$

Answer 2

(2x+3y+2z)^2
[a+b+c]^2=a^2+b^2+c^2+2ab+2bc+2ca

(2x+3y+2z)^2=(2x)^2+(3y)^2+(2z)^2+2×2x×3y
+2×3y×2z+2×2z×2x

=4x^2+9y^2+4z^2+12xy+12yz+8zx