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(2x-3y)एक्सप्लेन टू एक्स माइनस 3 बाय ऑल पावर 3 ​

Answer 1

ANSWER,

GIVEN:-

$\sf\therefore (2x-3y)^3$

NOW,

USING FORMULA,

$\sf\large\therefore\bold (x-y)^3=x^3-y^3-3xy(x-y)$

SOLUTION,

$\sf\implies (2x)^3-(3y)^3-3 \times (2x)(3y)(2x-3y)$

$\sf\implies 8x^3-27y^3-3 \times (6xy)(2x-3y)$

$\sf\implies 8x^3-27y^3-  (18xy)(2x-3y)$

$\sf\implies 8x^3-27y^3-36x^2y+54xy^2$

$\sf\underline\bold\star 8x^3-27y^3-36x^2y+54xy^2$

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Answer 2

$\huge\underline{\underline{\bold{\green{AnSwEr}}}}$

USING FORMULA,

$\sf\large\therefore\bold (x-y)^3=x^3-y^3-3xy(x-y)$

SOLUTION,

$\sf\implies (2x)^3-(3y)^3-3 \times (2x)(3y)(2x-3y)$

$\sf\implies 8x^3-27y^3-3 \times (6xy)(2x-3y)$

$\sf\implies 8x^3-27y^3-  (18xy)(2x-3y)$

$\sf\implies 8x^3-27y^3-36x^2y+54xy^2$

$\sf\underline\bold\star 8x^3-27y^3-36x^2y+54xy^2$

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