Question

expand (-2x+7y-z)^2 plz anyone answer this question its urgent ​

Answer 1

Answer:

Step-by-step explanation:

Expand exponent.

(-2x+7y-z)(-2x+7y-z)

(−2x+7y−z)(−2x+7y−z)

2) Expand by distributing sum groups.

-2x(-2x+7y-z)+7y(-2x+7y-z)-z(-2x+7y-z)

−2x(−2x+7y−z)+7y(−2x+7y−z)−z(−2x+7y−z)

3) Expand by distributing terms.

4{x}^{2}-14xy+2xz+7y(-2x+7y-z)-z(-2x+7y-z) 4x  2  −14xy+2xz+7y(−2x+7y−z)−z(−2x+7y−z)

4) Expand by distributing terms.

4{x}^{2}-14xy+2xz-14yx+49{y}^{2}-7yz-z(-2x+7y-z) 4x  2  −14xy+2xz−14yx+49y  2

−7yz−z(−2x+7y−z)

5) Expand by distributing terms.

4{x}^{2}-14xy+2xz-14yx+49{y}^{2}-7yz-(-2zx+7zy-{z}^{2}) 4x  2  −14xy+2xz−14yx+49y 2  −7yz−(−2zx+7zy−z  2 )

6) Remove parentheses.

4{x}^{2}-14xy+2xz-14yx+49{y}^{2}-7yz+2zx-7zy+{z}^{2} 4x 2 −14xy+2xz−14yx+49y2 −7yz+2zx−7zy+z  2

 

7) Collect like terms.

4{x}^{2}+(-14xy-14xy)+(2xz+2xz)+49{y}^{2}+(-7yz-7yz)+{z}^{2} 4x  2  (−14xy−14xy)(2xz+2xz)+49y 2  +(−7yz−7yz)+z  2

 

8) Simplify.

4{x}^{2}-28xy+4xz+49{y}^{2}-14yz+{z}^{2} 4x  2 −28xy+4xz+49y2 −14yz+z 2

 Hope it helps. plz mark as brainliest.

Answer 2

Answer:

solution :

${ - 2x + 7y - z) } ^{2} \\ \: ( - 2x + 7y - z)( - 2x + 7y - z) \\ - 2x( - 2x + 7y - z) + 7y( - 2x + 7y - z) \\ 4 {x}^{2} - 14xy + 2xz + 7y( - 2x + 7y - z) \\ 4 {x}^{2} - 28xy + 4xz + 49 {y}^{2} - 14yz + {z}^{2}$