Question

expand (2x+p-c)² - (2x - p+c)²​

Answer 1

Answer:

2(3xp-2xc)

Step-by-step explanation:

=(2x+p-c)² - (2x-p+c)

From (a+b+c)²=a²+b²+c²+2ab+2bc+2ca

=(4x²+p²+c²+2xp-2pc-2xc)-(4x²+p²+c²-4xp-2pc+2xc)

=4x²+p²+c²+2xp-2pc-2xc-4x²-p²-c²+4xp+2pc-2xc

=6xp-4xc

=2(3xp-2xc)

I hope it will help you. Thank you.

Answer 2

$\textbf{\huge\underline{\underline\red{Solution} : - }}</p><p> \\ \\ = > \bold{ ({2x + p - c})^{2} - ({2x - p + c})^{2} } \\ \\ \bold \purple{we \: use \: formula}\\ \\ \bold \red{ {a}^{2} - {b}^{2} = {(a + b)} \: \: {(a - b)} } \\ \\ \bold {\underline \orange{let}} \\ \bold {\red{a = ({2x +p - c}) \: \: and \: \: b = ({2x -p + c})}}\\ \\ = \bold{( ({2x +p - c} )+ ({2x -p + c})) } \: \: \bold{ (({2x +p - c )-( 2x -p + c})) } \\ \\ = \bold{( {2x +p - c} + {2x - p + c}) } \: \: \bold{ ({2x +p - c -2x + p - c}) } \\ \\ = \bold {(4x) \: \: {(2p - 2c)} } \\ \\ = \fbox{\fbox{\bold \red {2((2x) \: (p - c))}}} \\ \\ \fbox{ \bold \purple{i \: hope \: it \: helps \: you.}}$