Question

expand
(2x-y+3)(2x-y-3)
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Answer 1

Answer:

Solution:-

Expanded

$\mathtt \blue{( = 2x - y + 3)(2x - y - 3)}$

$\mathtt \blue{ = 2x(2x - y - 3) - y(2x - y - 3) + 3(2x - y - 3)}$

$\mathtt \blue{ = 4 {x}^{2} - 2xy - 6x - 2xy + {y}^{2} + 3y + {6x} - 3y - 9 }$

Simplify

$\mathtt \blue{ = 4 {x}^{2} - 2xy - 6x - 2xy + {y}^{2} + 3y + {6x} - 3y - 9 }$

$\mathtt \blue{ = {4x}^{2} - 2xy - 2xy - 6x + 6x + 3y - 3y + {y}^{2} + 9}$

$\mathtt \blue{ = {4x}^{2} - 4xy + {y}^{2} + 9 }$

Step-by-step explanation:

I hope this helps you mate