Question

expand (2x - y + z) sq using suitable identity​

Answer 1

Answer:

I think you meant expand (2x - y + z)² using suitable identity

$(2x - y + z)^2$

          $Using \: identity , \: ( a + b + c )^2 = a^2+b^2+c^2+2ab+2bc+2ca$

         $Where: \: a = 2x, \: b = - y , \: c = z$

$(2x)^2+(-y)^2+z^2+2(2x)(-y)+2(-y)z+2z(2x)$

$4x^2 + y^2 + z^2 - 4xy - 2yz + 4zx$

Answer 2

Answer:

(2x - y + z)²

= (2x)² + (-y)² + z² + 2. 2x.(-y) + 2.(-y).z + 2.z.2x

= 4x² + y² + z² - 4xy - 2yz +4zx

Identity used :—

$\boxed{ \bold{† \: (a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca} \: \: †}$