Math, asked by kabirbora, 6 months ago


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(2x+y-z)square​

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Answered by Anonymous
0

 {(2x + y - z)}^{2}  \\  \\ we \: know \\  {(a + b + c)}^{2}  =  {a}^{2}  +  {b}^{2}  +  {c}^{2}  + 2ab + 2bc + 2ca \\  \\ so \\  {(2x + y - z)}^{2}  =  \\  {(2x)}^{2}  +  {(y)}^{2}  +  {( - z)}^{2}  + 2(2x)(y) + 2(y)( - z) + 2( - z)(2x) \\  \\  = 4 {x}^{2}  +  {y}^{2}  +  {z}^{2}  + 4xy - 2zy - 4xz

Answered by RealSweetie
5

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