Question

Expand (3+4) whole square

Answer 1

Answer:

$\sf {(3 + 4)}^{2}$

$\sf \to {3}^{2} + 2(3 \times 4) + {4}^{2}$

$\sf \to9 + 2(12) + 16$

$\sf \to9 + 24 + 16$

$\sf \to49$

Answer 2

Answer:

see steps

Step-by-step explanation:

The given expression (4a−2b−3c)

2

can be solved as shown below:

(4a−2b−3c)

2

=(4a)

2

+(−2b)

2

+(−3c)

2

+(2×4a×(−2b))+(2×(−2b)×(−3c))+(2×(−3c)×4a)

(∵(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca)

=16a

2

+4b

2

+9c

2

−16ab+12bc−24ca

Hence, (4a−2b−3c)

2

=16a

2

+4b

2

+9c

2

−16ab+12bc−24ca.