Expand ( − 3)ଶ
using identities.
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Answer:
Solution:
(−2x+5y−3z) 2
is of the form(a+b+c)2a+b+c)2=a2+b2+c2+2ab+2bc+2ca
where a=−2x,b=5y,c=−3z
∴(−2x+5y−3z) 2
=(−2x) 2+(5y) 2 +(−3z) 2+2(−2x)(5y)+2(5y)(−3z+2(−3z(−2x)
=4x 2 +25y 2+9z 2−20xy−30yz+12zx.
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