Question

expand (3a-3b-4c)^2​

Answer 1

Answer:

${(x + y + z)}^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2yz + 2zx \\ {(3a - 3b - 4c)}^{2} = {3a}^{2} + { - 3b}^{2} + { - 4c}^{2} + 2(3a)( - 3b) + 2( - 3b)( - 4c) + 2( - 4c)(3a) \\ ={9a}^{2} + {9b}^{2} + {16c}^{2} - 12ab+ 24bc - 24ac$

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