Math, asked by parameshr2009, 2 days ago

Expand [3a-4b-3c]^2.

Answers

Answered by NishaanthA
1

Answer: 92−12−9−4(3−4−3)−3(3−4−3)

Explanation:

(3a-4b-3c)^2

(3a-4c-3c)(3a-4c-3c)

3(3−4−3)−4(3−4−3)−3(3−4−3)

92−12−9−4(3−4−3)−3(3−4−3)

Answered by rejilabobby
0

Answer:

(3a + 3a) - (4b + 4b) - (3c + 3c)

Step-by-step explanation:

As there is ^2 , you need to double the quantity inside the bracket/ braces i.e. ( 1a + 1b)^2 = (1a +1a)+ (1b + 1b)

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