expand....(3a+4b+5c)2ka whole sq
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Answered by
19
Hi
Nice question
Question:-
(3a + 4b + 5c)² = ?
Solution:-
Using identity
(x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx
Now,
= (3a)² + (4b)² + (5c)² + 2(3a)(4b) + 2(4b)(5c) + 2(5c)(3a)
= 9a² + 16b² + 25c² + 24ab + 40bc + 30ac
Hope this helps you.
Nice question
Question:-
(3a + 4b + 5c)² = ?
Solution:-
Using identity
(x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx
Now,
= (3a)² + (4b)² + (5c)² + 2(3a)(4b) + 2(4b)(5c) + 2(5c)(3a)
= 9a² + 16b² + 25c² + 24ab + 40bc + 30ac
Hope this helps you.
Anonymous:
thanku...
Answered by
8
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