Question

Expand (3a + 4b + 5c)whole square?
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Answer 1

$\huge{\underbrace{\mathbb{Answer}}}$

(3a+4b+5c)²

$\sf{\underline\blue{using}}$ (x+y+z)² = x²+y²+z²+2xy+2yz+ 2zx

$\sf{\underline\blue{putting x}}$ = 3a ,y = 4b, z= 5c

☞(3a²)+(4b²)+(5c²) + 2(3a)(4b) +2(4b)(5c)+2(5c)(3a)

☞9a²+16b²+25c²+(2×3×4)(a×b)+(2×4×5) (b×c) + (2×5×3) (a×c)

⇛9a²+16b²+25c²+24ab+40bc+30ac..

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hope this helps you :)