expand: (3a-5b-c)² solve the sum
Answers
Answered by
237
Heya !!
Here's your answer
To expand
(3a - 5b - c)²
It can be expanded using algebraic identity
(a + b + c)² = a²+ b²+ c² + 2ab + 2bc + 2ac
where,
a = 3a
b = (-5b)
c = ( -c)
So,
(3a +(-5b)+(-c)² = (3a)² + (-5b)² + (-c)² + 2(3a)(-5b) + 2(-5b)(-c) + 2(3a)(-c)
= 9a² + 25b² + c² - 30ab + 10bc - 6ac
is the answer
Here's your answer
To expand
(3a - 5b - c)²
It can be expanded using algebraic identity
(a + b + c)² = a²+ b²+ c² + 2ab + 2bc + 2ac
where,
a = 3a
b = (-5b)
c = ( -c)
So,
(3a +(-5b)+(-c)² = (3a)² + (-5b)² + (-c)² + 2(3a)(-5b) + 2(-5b)(-c) + 2(3a)(-c)
= 9a² + 25b² + c² - 30ab + 10bc - 6ac
is the answer
Anonymous:
please brainliest if helped :-)
Answered by
11
Answer:
9a^2+25b^2+c^2-30ab-10bc-6ca
Step-by-step explanation:
using identity (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
therefore
a=3a
a=3ab=-5b
a=3ab=-5bc=-c
while substituting the values u get
while substituting the values u get(3a)^2+(-5b)^2+(-c) ^2+(2*3a*-5b)+(2*-5b*-c)+(2*-c*3a)
while substituting the values u get(3a)^2+(-5b)^2+(-c) ^2+(2*3a*-5b)+(2*-5b*-c)+(2*-c*3a)= 9a^2+25b^2+c^2-30ab+10bc-6cahile
hope this helps u
hope this helps u plz mark this as brainliest
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