Math, asked by saurav163, 1 year ago

expand: (3a-5b-c)² solve the sum

Answers

Answered by Anonymous
237
Heya !!
Here's your answer

To expand

(3a - 5b - c)²

It can be expanded using algebraic identity
(a + b + c)² = a²+ b²+ c² + 2ab + 2bc + 2ac

where,
a = 3a
b = (-5b)
c = ( -c)

So,

(3a +(-5b)+(-c)² = (3a)² + (-5b)² + (-c)² + 2(3a)(-5b) + 2(-5b)(-c) + 2(3a)(-c)

= 9a² + 25b² + c² - 30ab + 10bc - 6ac
is the answer

Anonymous: please brainliest if helped :-)
saurav163: okk
Anonymous: :-)
Anonymous: thanks for the brainliest :-)
saurav163: np
Answered by sanvi200628
11

Answer:

9a^2+25b^2+c^2-30ab-10bc-6ca

Step-by-step explanation:

using identity (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

therefore

a=3a

a=3ab=-5b

a=3ab=-5bc=-c

while substituting the values u get

while substituting the values u get(3a)^2+(-5b)^2+(-c) ^2+(2*3a*-5b)+(2*-5b*-c)+(2*-c*3a)

while substituting the values u get(3a)^2+(-5b)^2+(-c) ^2+(2*3a*-5b)+(2*-5b*-c)+(2*-c*3a)= 9a^2+25b^2+c^2-30ab+10bc-6cahile

hope this helps u

hope this helps u plz mark this as brainliest

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