Question

expand (3a+6b+4c)^2 class 9th chapter polynomial​

Answer 1

Step-by-step explanation:

$\red{given = (3a+6b+4c)^{2} } \\ \purple{to \: find = expand \: this \: equation} \\ \pink{using \: (a + b + c) ^{2} formula} \\⟹ (3a) {}^{2} + (6b) {}^{2} + (4c) {}^{2} + 2(3a)(6b) + 2 (6b)(4c)+ 2(4c)(3a) \\ ⟹9a {}^{2} + 36b {}^{2} + 16c {}^{2} + 36ab + 48bc + 24ca \\ \rule{300pt}{3pt} \\ \begin{gathered}\boxed{ \rm{ \: \blue{ ⟹ thus \: the \: correct \: answer \: is \: 9a {}^{2} + 36b {}^{2} + 16c {}^{2} + 36ab + 48bc + 24ca..}\: }} \\ \end{gathered} </p><p></p><p> </p><p> </p><p> </p><p>$