expand (3a-7b-c)square using suitable identity
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Answered by
302
identity is (a+b+c)whole square = a^2+b^2+c^2+2ab+2bc+2ca
now expand it by putting a = 3a, b = (-7b), c= (-c)
substitute the values and you will get the answer
= 9a^2+49b^2+c^2-42ab+14bc-6ca
Answered by
4
Concept
Recall the formula we will use to solve the question.
(a+b+c)² = a² + b² + c²+ 2ab + 2bc + 2ac
Given
The expression (3a-7b-c)².
To find
We have to expand the given expression.
Solution
The expression is (3a-7b-c)²
Apply the formula
(3a-7b-c)² = (3a)²+(-7b)²+(-c)²+2*3a(-7b)+2*(-7b)(-c)+2*3b(-c)
= 9a²+49b²+c²-42ab+14bc-6ac
Hence the expand value is 9a²+49b²+c²-42ab+14bc-6ac.
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