Question

expand :(3a-b-2c)^2.​

Answer 1

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Using the identity

(a-b-c)²= (a²-b²-c²-2ab-2bc-2ca)

=> (3a-b-2c)²

=> (3a)²-(b)²-(2c)²-2(3a)(b)-2(b)(2c)-2(2c)(3a)

=> 9a²-b²-4c²-6ab-4bc-12ca

Answer 2

Answer:

Using the identity

(a-b-c)²= (a²-b²-c²-2ab-2bc-2ca)

=> (3a-b-2c)²

=> (3a)²-(b)²-(2c)²-2(3a)(b)-2(b)(2c)-2(2c)(3a)

=> 9a²-b²-4c²-6ab-4bc-12ca

Step-by-step explanation:

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