Math, asked by maqboolmaliyakkal7, 5 months ago

Expand (3x+1)3
using suitable identity .

Answers

Answered by vaibhav4601
3

Answer:

identity will be (a+b)³ = a³ + b³ + 3ab(a+b)

Step-by-step explanation:

(3x+1)³ = 27x³ + 1 + 9x(3x+1)

= 27x³ + 1 + 27x² + 9x

= 27x³ + 27x² + 9x + 1

Answered by TheWonderWall
10

Answer:

(3x + 1) ^{3}  \\  \\  = (3x) ^{3}  +  3(3x) ^{2}(1) + 3(3x)(1)^{2}   + (1) ^{3}  \\  \\  = 27x ^{3}  + 27x ^{2}  +9 x + 1 \\  \\ formula \: used \\  \\ (a + b) ^{3}  = a ^{3} + 3a ^{2}  b + 3ab ^{2} +  b ^{3}

hope it helps uH

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