Question

expand (3x-1)(3x+2)(3x-4)​

Answer 1

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(3x-1)(3x+2)(3x-4)

= (9x^2 + 6x - 3x - 2)(3x-4)

= (9x^2 - 3x - 2)(3x-4)

= (27x^3 - 9x^2 - 6x - 36x^2 + 12x + 8)

= 27x^3 - 45x^2 + 6x + 8

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Answer 2

☆ Question:

=> Expand (3x-1)(3x+2)(3x-4)

☆ Solution:

► (3x -1 ) ( 3x +2 ) ( 3x-4)

► (9x^2 + 6x - 3x - 2 ) ( 3x-4)

► ( 9x^2+3x-2) ( 3x - 4)

► 27x^3 -36x^2 + 9x^2 - 12 x -6x + 8

► 27x^3 - 27 x^2 - 18 x + 8

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