Expand (3x − 1)(3x+ 2)(3x − 4) using a suitable identity.
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Answered by
4
Step-by-step explanation:
we have to use identity 4 (x+a)(x+b)=x2+(a+b)x+ab
(3x+4)(3x-5)
=(3x+4){3x+(-5)}
here x=3x a=4 and b=-5
=3x2+{4+(-5)}+4×(-5)
=9x2-1-20
Answered by
1
Answer:
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Step-by-step explanation:
we know,
(x+a) (x+b) (x+c)=x³+(a+b+c) x²+(ab+bc+CA) x+abc
a= -1 , b=2 , c= -4 , x=3x
=(3x) ³ +(-1 + 2 + [-4] ) (3x) ² + ( [ -1 × 2] + [ 2×-4] + [ -4 ×
-1 ] ) 3x + (-1 × 2 × -4 )
= 27x³ + (-3) × 6x² +(-2)+ ( -8) + ( 4 ) × 3x + 8
= 27x³ - 18x² - 6 ×3x + 8
= 27x³ - 18x² - 18x + 8
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