Question

Expand (3x+1/3x)^3 pls give awnser

Answer 1

Answer:

(3x-1)^3.

Here we'll use the property of (a-b)^3

I.e. (a-b)^3 = a^3 - b^3– 3(a)(b)(a-b)

We get,

(3x-1)^3 = (3x)^3 - (1)^3 -3(3x)(1)(3x-1)

= 27x^3–1–27x^2+9x

= 27x^3 - 27x^2 +9x -1. which is the required expansion.

Mark as branliest

Answer 2

ANSWER:-

$\frac{ {(3x + 1)}^{3} }{ {(3x)}^{3} } \\ \\ = > \frac{ {(3x)}^{3} + {1}^{3} + 2(3x)(1)( 3x + 1)}{ {(3x)}^{3} } \\ \\ = > \frac{27 {x}^{3} + 1 + 6x(3x + 1)}{(3x)^{3} } \\ \\ = > \frac{27{x}^{3} + 1 + 18 {x}^{2} + 6x}{(3x)^{3} } \\ \\ = > \frac{27{x}^{3} + 18 {x}^{2} + 6x + 1}{27 {x}^{3} }$

Hence the expansion of (3x+1/3x)^3 is $\frac{27{x}^{3} + 18 {x}^{2} + 6x + 1}{27 {x}^{3} }$