Question

expand (3x+1/3x)(3x+1/3x)​

Answer 1

Question:

Expand $(3x+\frac{1}{3x})(3x+\frac{1}{3x})$

Given:

$(3x+\frac{1}{3x})(3x+\frac{1}{3x})$

To Find:

$(3x+\frac{1}{3x})(3x+\frac{1}{3x})$

Formula Used:

$(a+b)^2=a^2+b^2+2ab$

Solution:

$(3x+\frac{1}{3x})(3x+\frac{1}{3x})\\\\\\(3x+\frac{1}{3x})^2\\\\\\(a+b)^2=a^2+b^2+2ab\\\\\\(3x)^2+(\frac{1}{3x})^2+2\times3x\times\frac{1}{3x}\\\\\\9x^2+\frac{1}{9x^2}+2$

$9x^2+\frac{1}{9x^2}+2$

Answer:

$9x^2+\frac{1}{9x^2}+2$

Answer 2

refer to above answer