Question

expand 3x/2 +1 whole cube​

Answer 1

Step-by-step explanation:

(3x /( 2x +1 ))^3

(3x)^3 / (2x+1)3

(a+b)^3 = a^3 + 3a^2b+3ab^3+ b^3

(2x+1)^3 = (2x)^3 + 3×2x ×^2×1 + 3×2x×1^2 + 1^3

=

$8 {x}^{3} + 12 {x}^{2} + 6x + 1$

=

$(3x \div (2x + 1)) ^{3} = 27{x}^{3} \div 8{ x}^{3} + 12 { x}^{2} + 6{x}^{2} + 3x + 1$