Question

expand : (3x-2)³ answer this plz ​

Answer 1

We have:

$(3x-2)^3$

We have to expand the given expression $(3x-2)^3$.

Solution:

∴ $(3x-2)^3$

= $(3x)^{3} -3(3x)^{2} (2)+ 3(3x) (2^2)-2^3$ [ ∵ $(a-b)^3=a^3-3a^2b+3ab^2-b^3$]

= $27x^{3} -54x^2+ 36x-8$

∴ $(3x-2)^3$ = $27x^{3} -54x^2+ 36x-8$

Thus, the value of expandation of $(3x-2)^3$ is $27x^{3} -54x^2+ 36x-8$.