Math, asked by lhudup7624872202, 5 months ago

expand (3x-2)³ plz reply me fast...... ​

Answers

Answered by syedsadiq288
0

Step-by-step explanation:

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Answered by heramb11
0

Answer:

(3x-2)^3

(3x−2) 3

= (3x)^{3} -3(3x)^{2} (2)+ 3(3x) (2^2)-2^3(3x) 3

−3(3x)

2

(2)+3(3x)(2

2

)−2

3

[ ∵ (a-b)^3=a^3-3a^2b+3ab^2-b^3(a−b)

3

=a

3

−3a

2

b+3ab

2

−b

3

]

= 27x^{3} -54x^2+ 36x-827x

3

−54x

2

+36x−8

∴ (3x-2)^3(3x−2)

3

= 27x^{3} -54x^2+ 36x-827x

3

−54x

2

+36x−8

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