expand:(3x+2)whole cube
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Solution :
(i) (3x +2 )^3
= (3x)^3 + (2)^3 + 3.3x.2(3x+2)
= 27x^3 + 8 + 18x ( 3x+2)
= 27x^3 + 8 + 54x^2 + 36x
= 27x^3 + 54x^2 + 36x + 8
More Information : ( Identity Used )
(i) (x)^3 + (y)^3 + 3.x.y(x+y)
(i) (3x +2 )^3
= (3x)^3 + (2)^3 + 3.3x.2(3x+2)
= 27x^3 + 8 + 18x ( 3x+2)
= 27x^3 + 8 + 54x^2 + 36x
= 27x^3 + 54x^2 + 36x + 8
More Information : ( Identity Used )
(i) (x)^3 + (y)^3 + 3.x.y(x+y)
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