Math, asked by vc5019114, 8 months ago

expand (3X+2y+4z)^2​

Answers

Answered by Anonymous
3

Answer:

(3x+2y+4z)^{2}  =

Step-by-step explanation:

We know that (a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2ab + 2bc + 2ca.

Here, a = 3x, b= 2y, and c = 4z

(3x+2y+4z)^{2} = (3x)^{2} + (2y)^{2} + (4z)^{2} + 2(3x)(2y) + 2(2y)(4z) + 2(4z)(3x)

now, do the rest

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