Question

expand. (3x+3)^3. step by step pls​

Answer 1

Answer:

$(3x + 3) {}^{3} = 27x {}^{3} + 81x {}^{2} + 81x + 27$

Step-by-step explanation:

$(x + y) {}^{3} = x {}^{3} + y {}^{3} + 3xy(x + y) \\ (3x + 3) {}^{3} = (3x) {}^{3} + (3) {}^{3} + 3(3x)(3)(3x + 3) \\ (3x + 3) {}^{3} = 27x {}^{3} + 27 + 27x(3x + 3) \\ (3x + 3) {}^{3} = 27x {}^{3} + 81x {}^{2} + 81x + 27$

Answer 2

Since (a+b)³=a³+b³+3ab(a+b)

So (3x+3)³=(3x)³+(3)³+3(3x)(3)(3x+3)

=>(3x+3)³=27x³+27+27x(3x+3)

=>(3x+3)³=27x³+27+81x²+81x

=>(3x+3)³=27x³+81x²+81x+27

Hope it is helpful.