Question

Expand:- (3x +4y)^3please do fast tomorrow is my exam

Answer 1

$\huge\mathtt{\underline{\underline{\red{SOLUTION:-}}}}$

We know that

$\sf(a+b){}^{3}=a{}^{3}+b{}^{3}+3ab(a+b)$

where in the place of a=3x and b=4y

Then

$\mathtt{\underline{\underline{\red{According\:to\: question:-}}}}$

$\sf\implies (3x+4y){}^{3}\\ \\ \sf\implies (3x){}^{3}+(4y){}^{2}+3\times3x\times4y(3x+4y)\\ \\ \sf\implies 27x{}^{3}+64x{}^{3}+36xy(3x+4y)\\ \\ \sf\implies 27x{}^{3}+64y{}^{3}+108x{}^{2}y+144xy{}^{2}$

$\boxed{\purple{27x{}^{3}+64y{}^{3}+108x{}^{2}y+144xy{}^{2}}}$

Answer 2

┏─━─━─━─━∞◆∞━─━─━─━─┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✭✮

┗─━─━─━─━∞◆∞━─━─━─━─┛

WE KNOW THAT,

$(a + b) ^{3} = {a}^{3 } + {b}^{ 3} + 3ab(a + b)$

where a=3x and b=4y

ACCORDING TO QUESTION,

$>( 3x + 4y) ^{3}$

$= (3x) ^{3} + (4y)^{2} + 3 \times 3x \times 4y(3x + 4y)$

$= 27x ^{3} + 64 {x}^{3} + 36xy(3x + 4y)$

$= 27 {x}^{3} + 64 {x}^{3 } + 108 {x}^{2} y + 144x {y}^{2}$

▬▬▬▬▬ஜ۩۞۩ஜ▬▬▬▬▬▬