Question

Expand : (3X - y/2+4Z)²

please solved this Question.. .............​

Answer 1

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$\rm \star \: {(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ac)$

here ,

$\longrightarrow \: \rm \: a = 3x$

$\longrightarrow \rm \: b = \dfrac{ - y}{2}$

$\longrightarrow \: \rm \: c = 4z$

Now , just put the values in the Formula...

Answer 2

Answer:

$(3x - \frac{y}{2} + 4z)^2$ $=9x^2 + \frac{y^2}{4} + 16z^2 - 3xy - 4yz + 24zx$

Step-by-step explanation:

$(3x - \frac{y}{2} + 4z)^2\\=(3x - \frac{y}{2})^2 + 2(3x - \frac{y}{2}).4z + (4z)^2\\=(3x)^2 - 2.3x.\frac{y}{2} + (\frac{y}{2})^2 + 24zx - 4yz + 16z^2\\=9x^2 - 3xy + \frac{y^2}{4} + 24zx - 4yz + 16z^2$

$=9x^2 + \frac{y^2}{4} + 16z^2 - 3xy - 4yz + 24zx$