Expand: (4a-2b)³ please help
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Using identity V, we have
(4a – 2b – 3c)² = [4a + (-2b) + (-3c)]²
= (4a)² + (-2b)² + (-3c)² + 2(4a)(-2b) + 2(-2b)(-3c) + 2(-3c)(4a)
= 16b² + 4b² + 9c² – 16ab + 12bc – 24ac
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Answer:
64a³+128a²b+144ab²+8y
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