Question

expand (4a-2b-3c)^2
pls help

Answer 1

Answer:

$(4a - 2b - 3c)^2 = 16a^2+4b^2+ 9c^2 -16ab-24ac+12bc$

Step-by-step explanation:

Given :

To expand :

$(4a - 2b - 3c)^2$

Solution :

We know that,

$(a+b+c)^2=a^2 + b^2+c^2+2ab+2ac+2bc$

by substituting,

a → 4a , b → -2b , c → -3c,

We get,

⇒ $(4a - 2b - 3c)^2 = (4a)^2+(-2b)^2+(-3c)^2 +2(4a)(-2b)+2(4a)(-3c)+2(-2b)(-3c)$

⇒ $(4a - 2b - 3c)^2 = 16a^2+4b^2+ 9c^2 -16ab-24ac+12bc$