Question

· Expand (4a - 2b -- 3c). polynomials​

Answer 1

Answer:

(4a 2b 3c)2 = 16a2+ 4b2 + 9c2+16ab + 12bc - 24ca.

Step-by-step explanation:

(4a - 2b - 3c)2

= (4a)2 + (-2b)2+ (-3c)2 + (2 x 4a x (-2b)) + (2 (-2b) (-3c)) + (2 x (-3c) x( 4a)

((a+b+c)2 = a² + b° + c² + 2ab + 2bc + 2ca))

16a2 + 4b2 + 9c2 - 16ab + 12bc - 24ca

Hence, (4a 2b 3c)2 = 16a2+ 4b2 + 9c2+16ab + 12bc - 24ca.

I hope it's enough and helpful to you

Answer 2

if the question is (4a-2b-3c)²

then the answer is

by using formula of (a+b+c)²

(a+b+c+)²=a²+b²+c²+2ab+2bc+2ca

now ,a=4a

• b=-2b
• c=-3c

substitute the values in the formula

we get,

16a²+4b²+9c²-16ab+6bc-12ca

hope it helps u

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