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(4a+5b)^3
and
(5x-3y)^3
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Answered by
131
1)(4a+5b)³
(a+b) ³ = a³ +3a²b+ 3ab² +b³
(4a+5b)³ = (4a)³+ 3(4a)²(5b)+ 3(4a)(5b)²+(5b)³
= 64a³+ 240a²b + 300ab² + 125b³
2) (5x-3y)³
(a-b)³ = a³-3a²b +3ab²-b³
(5x-3y)³ = (5y)³+ 3(5x)²(3y) + 3(5x)(3y)²+ (3y)³
= 125y³+ 225x²y+ 135xy²+ 26y³
here's your answer...
hope it helps...!!
(a+b) ³ = a³ +3a²b+ 3ab² +b³
(4a+5b)³ = (4a)³+ 3(4a)²(5b)+ 3(4a)(5b)²+(5b)³
= 64a³+ 240a²b + 300ab² + 125b³
2) (5x-3y)³
(a-b)³ = a³-3a²b +3ab²-b³
(5x-3y)³ = (5y)³+ 3(5x)²(3y) + 3(5x)(3y)²+ (3y)³
= 125y³+ 225x²y+ 135xy²+ 26y³
here's your answer...
hope it helps...!!
samRyjel:
ur welcome nightmare1069
Answered by
0
Answer:Answer
Using the identity: (a+b)
3
=a
3
+b
3
+3a
2
b+3ab
2
Therefore,
(4a+5b)
3
=(4a)
3
+(5b)
3
+(3×(4a)
2
×5b)+(3×4a×(5b)
2
)=64a
3
+125b
3
+(15b×16a
2
)+(12a×25b
2
)
=64a
3
+125b
3
+240a
2
b+300ab
2
Hence, (4a+5b)
3
=64a
3
+125b
3
+240a
2
b+300ab
2
.
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