Question

expand (4p – 2q + 5r) the whole square

Answer 1

Answer:

Explanation:

The expression is (\mathrm{PQ}+5 \mathrm{r})^{2}(PQ+5r)2

We need to solve the expression using the identity (a+b)^{2}=a^{2}+2 a b+b^{2}(a+b)2=a2+2ab+b2

where a=PQa=PQ and b=5rb=5r

Expanding the expression, we have,

(\mathrm{PQ}+5 \mathrm{r})^{2}=(PQ)^{2} +2(PQ)(5r)+(5r)^{2}(PQ+5r)2=(PQ)2+2(PQ)(5r)+(5r)2

Simplifying the expression, we get,

(\mathrm{PQ}+5 \mathrm{r})^{2}=P^{2} Q^{2} +10PQr+25r^{2}(PQ+5r)2=P2Q2+10PQr+25r2

Thus, the solution of the expression (\mathrm{PQ}+5 \mathrm{r})^{2}(PQ+5r)2 is P^{2} Q^{2} +10PQr+25r^{2}P2Q2+10PQr+25r