expand (4p-7q)^3 by using standard formula
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Step-by-step explanation:
(4p-7q)²(4p-7q)
{(4p)²+(7p)²-2×4p×7q}(4p-7q)
(16p²+49q²-56pq)(4p-7q)
64p³+196pq²-224p²q-112p²q-323q³+392pq²
64p³+588pq²-336p²q-323q³
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0
Answer:
4p hole cube +3(4p)square ×79+3×4p×(7q) square = 64p cube +588pq square +336p square q +343q square
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