Math, asked by satishkr1996, 8 months ago

expand (4x+y+3z)² using suitable identity​

Answers

Answered by Anonymous
1

Answer:

(4x+y+3z)^2

{x+y+z}^2= x^2+ y^2+ z^2+ 2xy+ 2yz+ 2zx

= (4x)^2 + (y)^2 + (3z)^2 + 2*4x*y + 2*y*3z + 2*3z*4x

= 16x^2 + y^2 + 9z^2 + 8xy + 6yz + 12zx

Step-by-step explanation:

16x^2 + y^2 + 9z^2 + 8xy + 6yz + 12zx is the answer of your question

hope you find this answer helpful............

Similar questions