Expand (5/3x-1)3 using suitable identit
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Answer:
☞ (5/3x–1)³ = ??
Step 1:
Finding the Identity:
(x–y)³ = x³–y³+3xy²–3x²y.
Step 2:
Substituting values in the identity:
☞ x = 5/3x
☞ y = 1
☞ (5/3x–1)³ = (5/3x)³–(1)³+3(5/3x)(1)²–3(5/3x)²(1)
☞ (5/3x–1)³ = 125/27x³–1+5/x–25/3x²
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