Question

Expand [8 minus square root of 3]^2 giving your answer in form a+b square root of 3,hence find a+b

Answer 1

Answer:

$67 - 16 \sqrt{3}$

Step-by-step explanation:

this is what you want,

${(8 - \sqrt{3} )}^{2}$

$= {(8)}^{2} - 2 \times 8 \times \sqrt{3} + {( \sqrt{3}) }^{2}$

$= 64 - 16 \sqrt{3} + 3$

$= 67 - 16 \sqrt{3}$

which is your answer.

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