Question

Expand (999)^3 then the answer will be

Answer 1

999× 999× 999=99700299

Answer 2

Noting that it is much easier to calculate powers of 10 and 1 compared to 999, we can rewrite 999 as 1000−1=103−1 and apply the binomial theorem:

999^3=(103−1)^3

   =(3/0)(10^3)^3+(3/1)(10^3)^2(−1)+(3/2)(10^3)(−1)^2+(3/3)(−1)^3

   =10^9−3*10^6+3*10^3−1

   =1000000000−3000000+3000−1

   =997002999