expand (a+2b+3)² using identity
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Answered by
1
Answer:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
(a+2b+3)²= a²+(2b)²+(3)³+2a(2b)+2(2b)(3)+2a(3)
=a²+4b²+9+4ab+12b+6a
Answered by
2
Step-by-step explanation:
(a + 2b + 3)²
=> Identity used (a + b+ c)² = a² + b² + c² + 2ab + 2bc + 2ca
here, a = a, b = 2b and c = 3
=> (a + 2b + c)² = a² + (2b)² + 3² + 2×a×2b + 2×2b×3 + 2×3×a
=> a² + 4b² + 9 + 4ab + 12b + 6a
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