Question

expand (a+b+c)(a+b-c) using suitable identities​

Answer 1

Step-by-step explanation:

(a+b+c)(a+b-c)

=a×a+a×b-a×c+a×b+b×b-b×c+c×a+c×b-c×c

=a^2+ab-ac+ab+b^2-bc+ac+bc-c^2

=a^2+2ab+b^2-c^2