Expand and factorise: (2x – 3y)(3x + 4y)
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Hey mate thank for the question
Hope it helps
=(2x-3y)(3x+4y)
=6x^2+8xy-9xy-12y^2
=2x(3x+8y)-3y(3x+4y)
=(3x+8)(2x-3y)
2x-3y=0. , 3x+8y=0
2x=3y. 3x=-8y
x=3y/2. x=-8y/3
Hope it helps
=(2x-3y)(3x+4y)
=6x^2+8xy-9xy-12y^2
=2x(3x+8y)-3y(3x+4y)
=(3x+8)(2x-3y)
2x-3y=0. , 3x+8y=0
2x=3y. 3x=-8y
x=3y/2. x=-8y/3
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