Expand and simplify 4A+2B=3C
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Answer:
(4a-2b-3c)(4a-2b-3c)
using formula (a+b+c)(a+b+c) = a*a + b*b + c*c + 2ab + 2bc + 2ca
we can write like following
4a*4a + (-2b)*(-2b) + (-3c)*(-3c) + 2*4a*(-2b) + 2*(-2b)*(-3c) + 2*(-3c)*(4a)
= 16a*a + 4b*b + 9c*c - 16ab + 12bc - 24ac
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