Question

expand and simplyfy (x+y)2+(x-y)2

#dont spam#

Answer 1

Solution :-

$\boxed{{10 {x}^{2} + 10 {y}^{2} + 12 xy}}$

step by step :-

$\bf{{➥ ( x + 3y ) {}^{2} + ( 3x + y ) {}^{2} }}$

$\bf{{➥ x {}^{2} + 9y {}^{2} + 6 xy + 9 x {}^{2} + y {}^{2} + 6xy}}$

$\bf{{➥ 10 x {}^{2} + 10 y {}^{2} + 12 xy}}$

Hope you understand this answer mate : )

Answer 2

★ Solution :

= (x + 3y)² + (3x + y)²

= x² + 9y² + 6xy + 9x² + y² + 6xy

= 10x² + 10y² + 12xy

More explanation :

Integer, whole-valued positive or negative number or 0. The integers are generated from the set of counting numbers 1, 2, 3. and the operation of subtraction.

• When a counting number is subtracted from itself, the result is zero; for example, 4 − 4 = 0.