Math, asked by aijaz7056, 5 months ago

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and using
the identy of (P + 2q +r)²​

Answers

Answered by poonamkumari06928
1

Answer:

P+4q+r+4pq+4qr+2rp Ans

Step-by-step explanation:

We know that,

[( a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca]

= p^2+(2q)^2+(r)^2+2×p×2q+2×2q×r+2×r×p

= p+4q+r+4Pq+4qr+2rp Ans

Hope this will help you

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