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and using
the identy of (P + 2q +r)²
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Answer:
P+4q+r+4pq+4qr+2rp Ans
Step-by-step explanation:
We know that,
[( a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca]
= p^2+(2q)^2+(r)^2+2×p×2q+2×2q×r+2×r×p
= p+4q+r+4Pq+4qr+2rp Ans
Hope this will help you
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