Question

expand bracket 2A + 3 b + 4 C bracket close square​

Answer 1

Answer:

4a^{2}  + 9b^{2} + 16c^{2} + 12ab + 24bc + 16ca[/tex]

Step-by-step explanation:

$(2a + 3b + 4c )^{2}$

Using identity  $(a+b+c)^{2}$ = $a^{2}  + b^{2 } + c^{2} +2(ab + bc + ca)$

$(2a)^{2} + (3b)^{2}  + (4c)^{2}  + 2 [(2a*3b)+(3b*4c)+(4c*2a)]$

$4a^{2}  + 9b^{2} + 16c^{2} + 2 (6ab +12bc +8ca)\\4a^{2}  + 9b^{2} + 16c^{2} + 12ab + 24bc + 16ca$

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